For chemistry students · 4 minute read
What precipitate forms when silver nitrate reacts with potassium iodide?
Silver nitrate and potassium iodide form silver iodide, an insoluble yellow precipitate. Potassium and nitrate ions remain dissolved in the solution.
Try the yellow precipitate setupThe exact supported pair opens in a beaker. Nothing runs until you select Analyze.
Supported prediction
AgNO3(aq) + KI(aq) -> AgI(s) + KNO3(aq)
What the equation means
Silver nitrate and potassium iodide undergo a precipitation reaction. Insoluble silver iodide forms as a yellow solid while potassium and nitrate ions remain in solution. The molecular equation has a one-to-one reactant ratio.
Expected observation
A yellow silver iodide precipitate
OmniLab shows a bounded yellow precipitate cue inside the beaker to represent the expected silver iodide solid.
Three safety notes
Read these before any physical experiment
- 01
Wear gloves and splash goggles when handling silver nitrate.
- 02
Protect the silver iodide precipitate from strong light.
- 03
Collect silver-containing waste for approved disposal.
Keep exploring
Connect this observation to another reaction
These guides use the same pattern: predict the equation, identify the visible cue, then check what the virtual model leaves out.
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